4x^2-9x+42=0

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Solution for 4x^2-9x+42=0 equation:


Simplifying
4x2 + -9x + 42 = 0

Reorder the terms:
42 + -9x + 4x2 = 0

Solving
42 + -9x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
10.5 + -2.25x + x2 = 0

Move the constant term to the right:

Add '-10.5' to each side of the equation.
10.5 + -2.25x + -10.5 + x2 = 0 + -10.5

Reorder the terms:
10.5 + -10.5 + -2.25x + x2 = 0 + -10.5

Combine like terms: 10.5 + -10.5 = 0.0
0.0 + -2.25x + x2 = 0 + -10.5
-2.25x + x2 = 0 + -10.5

Combine like terms: 0 + -10.5 = -10.5
-2.25x + x2 = -10.5

The x term is -2.25x.  Take half its coefficient (-1.125).
Square it (1.265625) and add it to both sides.

Add '1.265625' to each side of the equation.
-2.25x + 1.265625 + x2 = -10.5 + 1.265625

Reorder the terms:
1.265625 + -2.25x + x2 = -10.5 + 1.265625

Combine like terms: -10.5 + 1.265625 = -9.234375
1.265625 + -2.25x + x2 = -9.234375

Factor a perfect square on the left side:
(x + -1.125)(x + -1.125) = -9.234375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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